(4x+5)(x^2+3x-4)=0

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Solution for (4x+5)(x^2+3x-4)=0 equation: 


Simplifying
(4x + 5)(x2 + 3x + -4) = 0

Reorder the terms:
(5 + 4x)(x2 + 3x + -4) = 0

Reorder the terms:
(5 + 4x)(-4 + 3x + x2) = 0

Multiply (5 + 4x) * (-4 + 3x + x2)
(5(-4 + 3x + x2) + 4x * (-4 + 3x + x2)) = 0
((-4 * 5 + 3x * 5 + x2 * 5) + 4x * (-4 + 3x + x2)) = 0
((-20 + 15x + 5x2) + 4x * (-4 + 3x + x2)) = 0
(-20 + 15x + 5x2 + (-4 * 4x + 3x * 4x + x2 * 4x)) = 0
(-20 + 15x + 5x2 + (-16x + 12x2 + 4x3)) = 0

Reorder the terms:
(-20 + 15x + -16x + 5x2 + 12x2 + 4x3) = 0

Combine like terms: 15x + -16x = -1x
(-20 + -1x + 5x2 + 12x2 + 4x3) = 0

Combine like terms: 5x2 + 12x2 = 17x2
(-20 + -1x + 17x2 + 4x3) = 0

Solving
-20 + -1x + 17x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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